This site makes extensive use of JavaScript.
Please enable JavaScript in your browser.
Live
PTR
10.2.5
PTR
10.2.6
HORDE: RAF anyone?
Return to board index
Post by
SixCube
I am wanting to take advantage of the recruit a friend program with anyone that plays on Horde faction only, Realm choice doesn't matter to me. Would be NICE to start the toons on a PVE realm though for faster leveling.
I will not be the one making the new account, so you will be paying the fees for all of account creation.
From the WoW website.
Step 1
The Invitation
Send a convenient email invitation to friends and family members, making it easy for them to create a new account and get started.
Step 2
Adventure Together
Meet the recruit in Azeroth (see Recruitment Form page for further details) and enjoy special in-game benefits for a full 90 days:
* Friend-to-friend summoning makes it easy to travel together.
* Bonus experience ensures faster leveling.
Step 3
Earn Rewards
If your friend/family member purchases a full copy of World of Warcraft and pays for a month of subscription time, you get 30 days of subscription time FREE!
If your friend/family member pays for two full months of subscription time, you'll receive an exclusive in-game zhevra mount!
Please post if you are interested.
Thanks for looking!
Post by
Vath
LoL, good luck finding someone.
Post by
ZoraLink
"Hey guys, you probably already have an account, but I definately want you to pay for ME to level faster! Thanks!"
Post by
jerms2k3
Heh just create your own second account and dual-box it :)
They released this feature right after I dual-boxed my priest up to level 70. That would have made things go much faster. If dual-boxing isn't an option for you, good luck in your search.
Post by
158948
This post was from a user who has deleted their account.
Post by
190432
This post was from a user who has deleted their account.
Post by
SixCube
There are new people, not wanting to spend a months time leveling.... Why not make them pay?
IBTL.
Post Reply
This topic is locked. You cannot post a reply.