This site makes extensive use of JavaScript.
Please
enable JavaScript
in your browser.
Live
PTR
Classic
TBC
Classic Theme
Thottbot Theme
Drop rate raids MOP
Post Reply
Return to board index
Post by
Kahnx
Hey im new in WoW till far it has been awesome. Recently i managed to get to item lvl 460 and i've been checking lately that the drop rate when using Raid finder is really low if u compare it to the normal raid (without the use of raid finder)... well until now i didnt know this. I´m really lost and kinda dissappointed cause it says that the drop rate in Raid Finder for a bow that i want in Mogu'chan is 0,02% !
Some detailed explanation and advice would be great!
Post by
Lancecaster
The drop rate from LFR is independent of other people in the raid - it's all individual. Here's the difference:
-With a regular raid, a boss drops 4 or so items, and these are distributed via rolling, master looter, etc. You are competing against RNG for what items will drop, AND competing against other people in the raid for any items that work for you.
-With LFR, each time the group kills a boss, the game does a hidden roll for each individual person. If you're fortunate, you automattically receive an item from that boss' loot table that works for your current spec. If not, then you get a bag with gold. I think the "drop rate" is about 15% to get an item.
It lines up approximately with the "old" LFR system, where you had to hope the item you wanted would drop AND hope that you won the roll. I personally have gone 2-3 weeks without a drop in several LFR segments, but have also had times when I received 3-4 pieces of gear from a single run. It's just RNG.
Edit: also, LFR and Regular/Heroic raids are independent lock-outs. You CAN do both if you choose.
Post by
226992
This post was from a user who has deleted their account.
Post by
Lancecaster
That may be true with 25M normal/heroic raids however 10m normal/heroic is 2 items per boss.
It makes the math even harder to compare. LFR is 25 man, so the number of individuals you are competing against in 25N/HC is equiv. to that.
Post Reply
You are not logged in. Please
log in
to post a reply or
register
if you don't already have an account.
© 2021 Fanbyte
